Find the magnitude of the acceleration (in m/s2) for an electron in a uniform electric field with a magnitude of 100 N/C.

and

Find the time it takes (in sec) for an electron initially at rest in a uniform electric field of 110 N/C to reach a speed of 0.01c (where c is the speed of light).

THANK YOU

To find the magnitude of acceleration for an electron in a uniform electric field, we can use the equation:

Acceleration = Electric Field / Charge of the Electron

Since the magnitude of the electric field is given as 100 N/C, and the charge of an electron is approximately -1.6 x 10^-19 C, we can substitute these values into the equation:

Acceleration = (100 N/C) / (-1.6 x 10^-19 C)

Calculating this expression will give us the magnitude of the acceleration in m/s^2.

Now, let's move on to the second question. To find the time it takes for an electron to reach a speed of 0.01c (where c is the speed of light) in a uniform electric field, we need to use the equation:

Time = Change in Velocity / Acceleration

We already have the acceleration from our previous calculation. The change in velocity is given as 0.01c, which means the initial velocity of the electron is 0 and the final velocity is 0.01 times the speed of light, or 0.01c.

Substituting the values into our equation, we get:

Time = (0.01c - 0) / Acceleration

Remember to convert the speed of light, c, which is approximately 3 x 10^8 m/s.

By calculating this expression, we can find the time it takes for the electron to reach a speed of 0.01c in seconds.