a 1kg object has kinetic energy of 1J when its speed is?
use
KE=0.5mv^2
where KE=1 J
m=1kg
substitute the values to find v..
God bless!!!
To find the speed at which a 1 kg object has a kinetic energy of 1 J, we can use the equation for kinetic energy:
Kinetic energy (KE) = (1/2) * mass * speed^2
Given that the mass is 1 kg and the kinetic energy is 1 J, we can rearrange the equation and solve for speed:
1 J = (1/2) * 1 kg * speed^2
Multiplying both sides of the equation by 2:
2 J = 1 kg * speed^2
Dividing both sides of the equation by 1 kg:
2 J / 1 kg = speed^2
Therefore, the speed at which the 1 kg object has a kinetic energy of 1 J is equal to the square root of 2 J / 1 kg.
Speed = √(2 J / 1 kg)
Speed ≈ 1.41 m/s
To find the speed of a 1kg object when it has a kinetic energy of 1J, we can use the formula for kinetic energy:
Kinetic energy (KE) = 1/2 * mass * (speed)^2.
Given that the mass (m) is 1kg and the kinetic energy (KE) is 1J, we can rearrange the formula to solve for the speed (v).
1J = 1/2 * 1kg * (v)^2
Now, let's solve for v:
Multiply both sides of the equation by 2 to isolate the (v)^2 term:
2 * 1J = 1kg * (v)^2
2J = (v)^2
Now, take the square root of both sides to solve for v:
√(2J) = √((v)^2)
√(2J) = |v| (it could be positive or negative)
Since speed is always a positive value, we can disregard the negative sign:
v = √(2J)
Therefore, the speed of the 1kg object when it has a kinetic energy of 1J is approximately equal to the square root of 2 Joules.