in a class one quarter of students have blonde hair and brown eyes and one third have brown eyes and blonde hair what fraction of the class in total have brown eyes

hmm. isn't "blonde hair and brown eyes" the same as "brown eyes and blonde hair" ?

It is saying that the whole class had either brown eyes or blonde hair. They are saying out of all the blonde haired students, 1/4 have blonde hair AND brown eyes. and it is saying out of all brown eyed students, 1/3 have brown eyes and blonde hair.

To find the fraction of the class that has brown eyes, we need to find the overlapping portion of the students who have both blonde hair and brown eyes, as well as those who have brown eyes and blonde hair.

Let's assume there are a total of x students in the class.

Given that one-quarter of the students have blonde hair and brown eyes, the fraction of these students can be represented as 1/4 * x.

Similarly, one-third of the students have brown eyes and blonde hair, which can be represented as 1/3 * x.

To find the fraction of the class that has brown eyes, we need to add the two fractions together:

Fraction with blonde hair and brown eyes: 1/4 * x
Fraction with brown eyes and blonde hair: 1/3 * x

Total fraction with brown eyes: (1/4 * x) + (1/3 * x)

To simplify this equation, we need a common denominator for 4 and 3, which is 12.

Total fraction with brown eyes: (3/12 * x) + (4/12 * x)

Combining the two fractions, we have:

Total fraction with brown eyes: (3x + 4x) / 12

Total fraction with brown eyes: (7x / 12)

Therefore, the fraction of the class that has brown eyes is 7x/12.

To find the fraction of the class that have brown eyes, we need to combine the fractions of students with brown eyes and blonde hair.

Let's assume there are a total of "x" students in the class.

Given that one-quarter (1/4) of the students have blonde hair and brown eyes, the number of students with both attributes would be (1/4) * x.

Similarly, one-third (1/3) of the students have brown eyes and blonde hair, which implies the number of students with both attributes would be (1/3) * x.

To find the total number of students with brown eyes, we need to add these two fractions together:

(1/4) * x + (1/3) * x

To simplify this expression, we can find a common denominator:

(3/12) * x + (4/12) * x

Combining the fractions:

(7/12) * x

Thus, the fraction of the class that have brown eyes is 7/12.