A volleyball is spiked so that it has an initial velocity of 14 m/s directed downward at an angle of 58° below the horizontal. What is the horizontal component of the ball's velocity when the opposing player fields the ball?
what is 14 cos58?
To find the horizontal component of the ball's velocity when it is fielded by the opposing player, we need to use the given initial velocity and angle.
The horizontal component of the velocity represents the motion of the ball in the x-direction, while the vertical component represents the motion in the y-direction. Since we are only interested in the horizontal component, we will focus on the x-direction.
The initial velocity of the ball can be broken down into its x and y components using trigonometry. The horizontal component can be calculated using the formula:
Vx = V * cos(θ)
Where:
- Vx is the horizontal component of velocity
- V is the initial velocity of the ball
- θ is the angle below the horizontal
Plugging in the given values into the formula, we have:
Vx = 14 m/s * cos(58°)
Calculating the value:
Vx = 14 m/s * cos(58°)
Vx = 7.07 m/s
Therefore, the horizontal component of the ball's velocity when the opposing player fields the ball is 7.07 m/s.