a baseball diamond is actually a square. the distance between bases is 90 feet. when a runner on first base tries to steal second, a catcher has to throw from home to second base.how far is it between home and second base?
What is 90 times the square root of two>
Idont no I need help
90 time the square root of two is 127.279 round it to 127.3
To find the distance between home and second base on a baseball diamond, we can use the Pythagorean theorem, which states that in a right triangle, the square of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the other two sides.
In this case, we have a square shape, with each side measuring 90 feet. Since the distance between first and second base is the diagonal of the square, it forms a right triangle with the sides of the square as its legs. The diagonal is equivalent to the hypotenuse of the right triangle we can form.
Using the Pythagorean theorem, we can calculate:
Diagonal^2 = Side1^2 + Side2^2
Diagonal^2 = 90^2 + 90^2
Diagonal^2 = 8,100 + 8,100
Diagonal^2 = 16,200
Taking the square root of both sides gives us:
Diagonal = √16,200
Diagonal ≈ 127.28 feet
Therefore, the distance between home and second base on a baseball diamond is approximately 127.28 feet.