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Physics 124

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A projectile is fired from the top of a cliff at 14.2 m/s at an angle of 36.9 degrees below the horizontal, and strikes water at the same level as the base of the cliff 3.51 seconds later. (Assume g=10.0 m/s2.)
How high was the top of the cliff above the water?

  • Physics 124 -

    all we care about is the downward velocity. Initially that is

    14.2 cos -36.9° = -11.36 m/s

    so, starting from height H, the height after t seconds is

    -11.36t - 4.9 t^2
    at t=3.51,
    h = -100.24 m

    So, the cliff is 100.24m high

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