Calculus
posted by batmo .
Write the polar equation in rectangular form. r = 12 sin theta
Write the rectangular equation (x + 7)^2 + y^2 = 49 in polar form

r = 12 sinθ
r^2 = 12r sinθ
x^2+y^2 = 12x
x^2  12x + y^2 = 0
(x6)^2 + y^2 = 36
This one is just the reverse process:
(x+7)^2 + y^2 = 49
x^2 + 14x + y^2 = 0
x^2 + y^2 = 14x
r^2 = 14r cosθ
r = 14 cosθ 
thank you!

I mixed up x and y in the 1st one!
x^2+y^2 = 12y
x^2  12y + y^2 = 0
x^2 + (y6)^2 = 36
Also, the 2nd one could just as well have been written r = 14cosθ. It would just draw the circle from the left, rather than from the right.
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