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Physics

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A policeman travelling 60 km/h spots a speeder ahead , so he accelerates his vehicle at a steady rate of 2.22 m/s^2 for 4.00 s, at which time he catches up with the speeder.
a) How fast was the policeman travelling in m/s?
b) How fast is the police car travelling after 4.00 s? Give answer in both m/s and km/h?
c) If the speeder has a constant velocity, sketch the motion of both the speeder and police car on a speed vs. time graph?

  • Physics -

    See your 9:32am post.

  • Physics -

    a.) 25.6m/s

  • Physics -

    60km/h*1km/1000m=6000m/h
    6000m/h*1h/3600=16.6m/s

    v=Vo+at
    v=16.6+(2.22)(4.00)=25.48 m/s

  • Physics -

    a)60km/h*1km/1000m=6000m/h
    6000m/h*1h/3600=16.6m/s

    v=Vo+at
    v=16.6+(2.22)(4.00)=25.48 m/s

    b)

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