At 2068.44kPaa, 37.8 celcius, 0.142 cubic meter of methane have a total mass of 1.82kg. Using avogadro's principle find the mass of carbong dioxide contained in a 0.85cubic meter tank at 2068.44kPaa,37.8 celsius
1.82 kg x (0.850/0.142) x (1 mol CO2/1 mol CH4) x (44 g CO2/1 mol CO2) x (1 mol CH4/16 CH4) = ?
why(0.85/0.145) if mx/my = vy/vx...mx = my(0.145/0.85) i have that doubt
To find the mass of carbon dioxide contained in a 0.85 cubic meter tank at 2068.44 kPaa and 37.8 degrees Celsius, we can use Avogadro's principle to calculate the number of moles of methane in the tank.
First, let's find the number of moles of methane using the Ideal Gas Law equation:
PV = nRT
Where:
P = pressure (in Pascal)
V = volume (in cubic meters)
n = number of moles
R = gas constant (8.314 J/(mol⋅K))
T = temperature (in Kelvin)
Step 1: Convert the pressure from kPaa to Pascal:
2068.44 kPaa * 1000 = 2068440 Pa
Step 2: Convert the temperature from Celsius to Kelvin:
37.8 degrees Celsius + 273.15 = 311.95 K
Step 3: Solve for the number of moles (n):
n = (PV) / (RT)
n = (2068440 Pa * 0.142 m3) / (8.314 J/(mol⋅K) * 311.95 K)
Calculating the above expression will give you the number of moles of methane in the tank.
Next, we can use the balanced chemical equation for the combustion of methane to calculate the mass of carbon dioxide produced:
CH4 + 2O2 -> CO2 + 2H2O
According to the equation, 1 mole of methane produces 1 mole of carbon dioxide. So, the number of moles of carbon dioxide will be the same as the number of moles of methane.
Finally, we can calculate the mass of carbon dioxide using the molar mass of carbon dioxide (44.01 g/mol) and the number of moles of carbon dioxide:
Mass of carbon dioxide = number of moles of carbon dioxide * molar mass of carbon dioxide
Note: If you provide the molar mass of methane, a more accurate calculation can be performed.
To find the mass of carbon dioxide contained in a 0.85 cubic meter tank at 2068.44 kPaa and 37.8 degrees Celsius, we can use Avogadro's principle to relate the volumes and molar masses of the two gases.
Avogadro's principle states that equal volumes of gases, at the same temperature and pressure, contain an equal number of molecules.
First, let's calculate the number of moles of methane in the given conditions.
1. Convert 37.8 degrees Celsius to Kelvin:
Celsius to Kelvin = Celsius + 273.15
T = 37.8 + 273.15 = 311.95 K
2. Apply the ideal gas law to find the number of moles of methane:
PV = nRT, where R is the ideal gas constant (approximately 8.314 J/(mol·K))
Rearranging the formula, we have:
n = PV / RT
n = (2068.44 kPaa * 10^3 Pa/kPa) * (0.142 m^3) / [(8.314 J/(mol·K)) * 311.95 K]
Note: We convert kPaa to Pascals (Pa) by multiplying by 10^3 to get the correct units.
n ≈ 0.8489 moles
Now, we need to find the mass of carbon dioxide, considering that the ratio between the moles of methane and carbon dioxide is 1:1 based on the balanced chemical equation.
The molar mass of methane (CH4) is approximately 16.04 g/mol.
The molar mass of carbon dioxide (CO2) is approximately 44.01 g/mol.
So, for 0.8489 moles of methane, we will have 0.8489 moles of carbon dioxide, which is also equal to the mass of carbon dioxide.
Finally, to find the mass of carbon dioxide in grams, we multiply the number of moles by the molar mass:
Mass of carbon dioxide = 0.8489 moles * 44.01 g/mol
Therefore, the mass of carbon dioxide contained in a 0.85 cubic meter tank at 2068.44 kPaa and 37.8 degrees Celsius is approximately 37.31 grams.