28.5g of iron shot is added to a graduated cylinder containing 45.50mL of water. The water level rises to the 49.10mL mark. From this information, calculate the density of the iron.

volumeshot=differencwe in water level

densityshot=massshot/volumeshot

Ok awesome! But I'm a bit confused as to what volume shot, density and mass shot mean?

volume shot means volume of the shot, density shot and mass shot means density of the shot and mass of the shot. Those are spelled out in your problem. For example the mass of the iron shot is 28.5 g.

To calculate the density of the iron, you need to use the formula: Density = Mass / Volume.

1. First, you need to determine the mass of the iron. The question states that 28.5g of iron shot was added. Therefore, the mass of the iron is 28.5g.

2. Next, you need to determine the volume of the iron. To do this, you need to subtract the initial volume of water from the final volume of the water. The initial volume of water is given as 45.50mL, and the final volume after adding the iron is given as 49.10mL. Therefore, the volume of the iron is 49.10mL - 45.50mL = 3.60mL.

3. Now you can calculate the density. Plug in the values into the formula:

Density = Mass / Volume

Density = 28.5g / 3.60mL

4. Finally, divide the mass (in grams) by the volume (in milliliters) to get the density of the iron.

Density = 28.5g / 3.60mL ≈ 7.92 g/mL.

Therefore, the density of the iron is approximately 7.92 g/mL.

30.5