physics
posted by Emily .
A bicycle has a speed of 7.5m/s at 4.3sec and a constant acceleration of 2.6m/s^2. the bicycle is at the origin (on the positive xaxis) when 1.2sec. How far from the origin is the bike at 7sec? Answer in units of m

v=v₀ +a•t
v₀ = va•t = 7.5 2.6•4.3 = 3.68 m/s.
x= x₀ + v₀•t +a•t²/2
x₀=x v₀•t a•t²/2 =0 – (3.68•1.2)  2.6•1.2²/2 = 4.416  0.052 = 4.364 m,
x= x₀ + v₀•t +a•t²/2 =
= 4.364 – 3.68•7 + 2.6•7²/2 =
= 4.364 – 25.76 + 63.7 = 42.304 m.