calculus
posted by John .
A hole of a radius of 1cm is pierced in a sphere of a 4cm radius. Calculate the volume of the remaining sphere.
I know that the volume of a sphere with an exterior radius is of:
V = pie(R^2  r^2) dH
where R^2 is the exterior surface area and r^2 is the interior surface area. dH is the thickness.
How would I go about finding the thickness? And for R and r, do I simply just plug in the values that are given to me?
Thank you.
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