This is the same equation as before just with different numbers.
y=yo + (vo sin Q) t - 1/2gt^2
This time the numbers are:
0 = 1.005 + (3.021 sin 30)t - 1/2(9.8)t^2
4.9t^2 - 1.5105 - 1.005 = 0
This is the part where I am stuck. Did I do this correctly? sin 30 = 0.50 X 3.021 = 1.5105 and then I would subtract this from 1.005
so then it would be 1.5105 - 1.005 = 0.5055 / 4.9 and square root it.
Math(Please check) - Reiny, Thursday, September 13, 2012 at 10:29am
You are making a similar mistake to yesterday's error.
Yesterday you just magically tagged a t at the end of the first term, now you are dropping the t from the second term
your equation of
0 = 1.005 + (3.021 sin 30)t - 1/2(9.8)t^2
looks ok, assuming your replacement values were correct
then
0 = 1.005 + 1.5105t - 4.9t^2 , since sin 30�‹ = 1/2
4.9t^2 - 1.5105t - 1.005 = 0 , look at yours
you will have to use the quadratic formula
t = (1.5105 �} �ã(1.5105^2 - 4(4.9)(-1.005) )/9.8
= .... you do the button-pushing
Math(Please check) - Steve, Thursday, September 13, 2012 at 10:33am
I think you dropped a t:
4.9t^2 - 1.5105t - 1.005 = 0
the coefficients are correct, so now you just have to solve the quadratic equation.
t = 0.154 �} �ã0.229
How did you get 0.154 and 0.229? When I try to complete the quadratic equation I am not getting these numbers.
use the quadratic formula.
t = [1.5105 +/- sqrt(1.5105^2 + 4*4.9*1.005)]/(2*4.9)
= [1.5105 +/- sqrt(21.9796)]/9.8
= (1.5105 +/- 4.6882)/9.8
= -0.324 or 0.632
Hmm. you are correct. Don't know how I came up with those bogus values. Probably cut/pasted from somewhere else. Good catch.
which of the following is a highest value ?15/16 b. 5/8 c. 3/4.
To solve the quadratic equation, you can use the quadratic formula:
t = (-b ± √(b^2 - 4ac))/2a
In the equation, a = 4.9, b = -1.5105, and c = -1.005. So, substituting these values into the quadratic formula, we get:
t = (-(-1.5105) ± √((-1.5105)^2 - 4(4.9)(-1.005)))/(2(4.9))
Simplifying further:
t = (1.5105 ± √(2.280301 - (-19.6)(-1.005)))/9.8
= (1.5105 ± √(2.280301 - 19.4918))/9.8
= (1.5105 ± √(-17.211499))/9.8
Since the value inside the square root is negative, we know that the equation has no real solutions. This means there are no values of t that satisfy the equation.
Therefore, there are no valid solutions for t in this case.