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An automobile accelerates from rest at 1.3m/s^2 for 19s. The speed is then held constant for 23s, after which there is an acceleration of -0.9m/s^2 until the automobile stops.
What total distance was traveled?
Answer in units of km.

  • physics -

    X1 = (1/2)a*19^2 = 234.7 m
    Attained velocity:
    Vmax = 1.3*19 = 24.7 m/s
    X2 = 24.7 * 23 s = 568.1 m
    X3 = (average speed)*(deceleration time)
    = (Vmax/2)*(Vmax/a)= ___?

    Add them up for total distance, and convert to km.

  • physics -

    here is another way:
    make it to X1,X2,X3
    X1=(1/2)(1.3*19)(19)
    X2=(1.3*19)(23)
    X3=(1.3*19)/(0.9)(1/2)(1.3*19)

    total distance = X1+X2+X3

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