Physics

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Runner A is initially 2.4 km west of a flagpole and is running with a constant velocity of 8.4 km/h due east. Runner B is initially 2.2 km east of the flagpole and is running with a constant velocity of 7.4 km/h due west. What will be the distance of the two runners from the flagpole when their paths cross?

Answer: ____ km from the flagpole due (east, west, south or north)

  • Physics -

    D = 2.2 -(-2.4) = 4.6 km = Distance between runners.

    Va*t + Vb*t = 4.6.
    8.4t + 7.4t = 4.6
    15.8t = 4.6
    t = 0.291 Hours.

    Da = Va*t = 8.4km/h * 0.291h=2.4444km.=
    Dist. ran by runner A.
    2.4444-2.400=0.044 km=East of flagpole.

    Db = Vb*t = 7.4km/h * 0.291h=2.1534 km.=
    Dist. ran by runner B.
    2.2000 - 2.1534 = 0.0466 km East of
    flagpole.

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