algerbra 2
posted by Anonymous .
the perimeter of the rectangular playing field is 462 yards. The length of the field is 5 yards less than the triple width. What are the dimensions of the playing field.

P = 2L + 2W
462 = 2(3W  5) + 2W
462 = 6W  10 + 2W
462 = 8W  10
462 + 10 = 8W
472 = 8W
59 = W
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