# algerbra 2

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the perimeter of the rectangular playing field is 462 yards. The length of the field is 5 yards less than the triple width. What are the dimensions of the playing field.

• algerbra 2 -

P = 2L + 2W

462 = 2(3W - 5) + 2W

462 = 6W - 10 + 2W

462 = 8W - 10

462 + 10 = 8W

472 = 8W

59 = W

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