college algebra
posted by ann :) .
12x+4y+2z=7 (1)
3x12y+6z=4 (2)
9x16y+4z=3 (3)
solve the system
just need the steps how to do it

I would go for the y's
3 times the first added to the 2nd >
4 times the first added to the 3rd >
you now have two equations with only x and z
try to finish it.
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