It takes 62 mL of 0.124 M KOH to neutralize
46.7 mL of H2SO4 solution. What is the
concentration of the H2SO4 solution?
Answer in units of moles/liter
2KOH + H2SO4 = K2SO4 + 2H2O
mols KOH = M x L = ?
mols H2SO4 = 1/2 that--Look at the coefficients in the balanced equation.
M H2SO4 = mols H2SO4/L H2SO4. You know L H2SO4 and mols, solve for M.
To find the concentration of the H2SO4 solution, we can use the concept of stoichiometry and the equation of the reaction between KOH and H2SO4.
The balanced equation for the reaction is:
2 KOH + H2SO4 -> K2SO4 + 2 H2O
From the equation, we can see that 2 moles of KOH react with 1 mole of H2SO4.
Given:
Volume of KOH solution = 62 mL = 0.062 L
Molarity of KOH solution = 0.124 M
Now, we can use the equation M1V1 = M2V2 to find the concentration of H2SO4 solution.
Let's substitute the given values into the equation:
(0.124 M) * (0.062 L) = M2 * (0.0467 L)
Rearranging the equation to solve for M2:
M2 = (0.124 M * 0.062 L) / 0.0467 L
Calculating the concentration of the H2SO4 solution gives:
M2 = 0.1658 M
Therefore, the concentration of the H2SO4 solution is 0.1658 moles/liter.