Calculate the volume of water, in milliliters, that would be displaced by a piece of gold weighing 18.2g.

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To calculate the volume of water displaced by a piece of gold weighing 18.2g, we need to use the concept of density. Density is a measure of how much mass is packed into a given volume.

First, we need to know the density of gold. The density of gold is approximately 19.3 grams per cubic centimeter (g/cm³) or 19.3 × 1000 kilograms per cubic meter (kg/m³).

Next, we need to convert the weight of the gold from grams to kilograms, as density is typically given in kilograms per cubic meter. To do this, divide the weight of gold by 1000 since 1 kilogram is equal to 1000 grams:

18.2 g ÷ 1000 = 0.0182 kg

Now we can calculate the volume of the gold. We use the formula:

Volume = Mass / Density

Volume = 0.0182 kg / 19.3 × 1000 kg/m³

Volume = 0.0182 kg / 19300 kg/m³

Volume = 0.000000942 m³

Since we want the volume in milliliters, we can convert cubic meters to milliliters by multiplying by 1,000,000 (1 m³ = 1,000,000 mL):

Volume = 0.000000942 m³ × 1,000,000 mL

Volume = 0.942 mL

Therefore, the volume of water displaced by a piece of gold weighing 18.2g is approximately 0.942 mL.