Math-Perimeter

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I just need to know how to use the perimeter formula to work this out (dont give answer)

A rectangular certicate 8 in. by 10 in. will have a frame 1 1/2 in. wide surrounding it. What is the perimeter of the outside edge of the frame?

  • Math-Perimeter -

    P = 2L + 2W

    8 + 3 = 11

    10 + 3 = 13

    The outside of the frame is 11 by 13.

  • Math-Perimeter -

    I don't like the way the problem is stated. A 1-1/2" wide frame can never go around a certificate that is 8 x 10". Ms Sue has interpreted the problem the only way it makes sense. I think the problem should have said that a frame was placed around the certificate with a space of 1-1/2". (To make it even clearer it could have added, on each side as well as top and bottom of the certificate.)

  • Math-Perimeter -

    Thanks! :)

  • Math-Perimeter -

    A 167
    p23

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