A machine gun fires 20 bullets per second in to a target. Each bullet weight 10 gm and has a speed of 1500m/s; Find the Force necessary to hold the gun in position.
300 N
i can't solve this problem please tell me or solve this question
To find the force necessary to hold the gun in position, we need to consider the momentum of each bullet and the rate at which the bullets are fired.
First, let's calculate the momentum of each bullet:
Momentum = mass * velocity
The mass of each bullet is given as 10 grams, which we need to convert to kilograms for consistent units.
Mass of each bullet = 10 grams = 10/1000 = 0.01 kg
The velocity of each bullet is given as 1500 m/s.
Momentum of each bullet = 0.01 kg * 1500 m/s
Momentum of each bullet = 15 kg⋅m/s
Now, we can find the total momentum per second, considering the rate at which the bullets are fired:
Total momentum = momentum per bullet * number of bullets per second
The momentum per bullet is 15 kg⋅m/s, and the number of bullets per second is given as 20.
Total momentum = 15 kg⋅m/s * 20
Total momentum = 300 kg⋅m/s
Finally, we know that force is the rate of change of momentum:
Force = change in momentum / time
The change in momentum is equal to the total momentum (300 kg⋅m/s), and the time interval is 1 second since we are considering the force required to hold the gun in position for 1 second.
Force = 300 kg⋅m/s / 1 s
Force = 300 N
Therefore, the force necessary to hold the gun in position is 300 Newtons.