how many milliliters of a 0.9 molar HCl solution are needed to react completely with 12 grams of zinc according to the following equation 2HCl+ Zn yields ZnCl2+ H2
Convert 12 g Zn to mols.
Using the coefficients in the balanced equation, convert mols Zn to mols HCl.
Then use M = mols/L to convert mols HCl to L, then to mL.
To determine the volume of the 0.9 M HCl solution needed to completely react with 12 grams of Zn, we need to follow these steps:
Step 1: Calculate the molar mass of Zn.
The molar mass of Zn is 65.38 g/mol.
Step 2: Convert the given mass of Zn to moles.
Divide the given mass (12 grams) by the molar mass of Zn to convert to moles:
12 grams / 65.38 g/mol = 0.1837 mol
Step 3: Use the balanced equation to determine the moles of HCl required.
From the balanced equation, we know that the stoichiometric ratio between HCl and Zn is 2:1. This means that for every 2 moles of HCl, 1 mole of Zn reacts. Therefore, the moles of HCl required will be half the moles of Zn.
0.1837 mol Zn × (2 mol HCl / 1 mol Zn) = 0.3674 mol HCl
Step 4: Use the molarity of HCl to calculate the required volume.
The molarity (0.9 M) is defined as moles of solute per liter of solution (mol/L). Rearranging the equation gives:
Molarity (M) = Moles of solute / Volume of solution (L)
Rearranging the equation, we find:
Volume of solution (L) = Moles of solute / Molarity (M)
Now, substitute the values into the equation:
Volume of solution (L) = 0.3674 mol HCl / 0.9 mol/L = 0.4082 L
Step 5: Convert the volume from liters to milliliters (mL).
Since 1 L = 1000 mL, multiply the volume in liters by 1000 to obtain the volume in milliliters:
0.4082 L × 1000 mL/L = 408.2 mL
Therefore, approximately 408.2 milliliters of the 0.9 M HCl solution are needed to react completely with 12 grams of zinc.
To find the amount of HCl solution needed to react with 12 grams of zinc, you will need to use stoichiometry and dimensional analysis. Here's how you can solve it step by step:
Step 1: Determine the molar mass of zinc (Zn).
The molar mass of zinc (Zn) is 65.38 g/mol.
Step 2: Use the molar mass of zinc to calculate the number of moles.
To find the number of moles, divide the mass of zinc (12 grams) by its molar mass:
Number of moles = Mass (g) / Molar mass (g/mol)
Number of moles = 12 g / 65.38 g/mol
Number of moles = 0.1835 mol (rounded to four decimal places)
Step 3: Apply stoichiometry to determine the ratio between HCl and zinc.
From the balanced equation, the stoichiometric ratio between HCl and Zn is 2 moles of HCl:1 mole of Zn.
Thus, 2 moles of HCl are required to react with 1 mole of Zn.
Step 4: Calculate the amount of HCl solution required.
Multiply the number of moles of zinc by the stoichiometric ratio:
Number of moles of HCl = Number of moles of zinc × (2 moles of HCl / 1 mole of Zn)
Number of moles of HCl = 0.1835 mol × (2 / 1)
Number of moles of HCl = 0.367 mol
Step 5: Convert moles to milliliters using the concentration of the HCl solution.
The concentration of the HCl solution is given as 0.9 M (0.9 mol/L).
To convert moles to milliliters, we need to know the volume of the solution that contains 1 mole of HCl.
Volume (L) = Number of moles / Concentration (mol/L)
Volume (L) = 0.367 mol / 0.9 mol/L
Volume (L) = 0.4078 L (rounded to four decimal places)
To convert from liters to milliliters, multiply by 1000:
Volume (mL) = 0.4078 L × 1000 mL/L
Volume (mL) = 407.8 mL
Therefore, approximately 407.8 milliliters of a 0.9 Molar HCl solution are needed to react completely with 12 grams of zinc.