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College Physics

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An object moves with constant acceleration 4.95 m/s2 and over a time interval reaches a final velocity of 13.2 m/s.
(a) If its initial velocity is 6.6 m/s, what is its displacement during the time interval?

(b) What is the distance it travels during this interval?

  • College Physics -

    a) 13.2
    13.2^2=6.6^2+2(4.95)(ΔX)
    174.24= 43.56+9.9ΔX
    130.68=9.9ΔX
    ΔX=13.2

    b)6.6+13.2/2=13.2/t
    9.9=13.2/t
    t= 1.33

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