Physics

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ball starts from rest under constant acceleration. If it travels a distance of 20.0 cm after time t, how far from the starting point is it after time 2t?
Answer

40.0 cm.

60.0 cm.

80.0 cm.

100.0 cm.

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  • Physics -

    D2/D1 = 0.5a*(2t)^2/0.5a*t^2.
    D2/D1 = 0.5a*4t^2/0.5a*t^2
    D2/D1 = 4t^2/t^2 = 4.

    D2/20 = 4
    D2 = 80 cm.

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