Post a New Question


posted by .

How would you prepare 500.0 of an aqueous solution of glycerol with a vapor pressure of 24.8mm Hg at 26 degree Celsius (vapor pressure of pure water=25.21mm Hg)? assume the density of the solution to be 1.00 g/mL.

  • Chemistry -

    500.0 what? I'll assume you meant 500.0 mL.

    Psoln = XH2O*Po
    Substitute and solve for XH2O = mole fraction H2O to produce vapor pressure of 24.80 mm.
    If we let x = grams glycerol, then 500-x = grams H2O
    mols glycerol = x/92.09
    mols H2O = (500-x)/18.015
    Plug into mole fraction H2O
    nH2O/(nH2O + nglycerol) = XH2O and solve for g glycerol and g H2O.

Answer This Question

First Name
School Subject
Your Answer

Related Questions

More Related Questions

Post a New Question