c= q/m*(delta)T

q= heat or energy, measured in joules (J)
c= specific heat of the substance
m= mass of substance
(delta)T= change in temperature

It requires 14,749 J to heat 75.0 g of water from 20.0 degrees C to 67.0 degrees C?

The correct formula:

q = mcΔT
or c = q/[(m)(ΔT)]

http://chemistry.about.com/od/workedchemistryproblems/a/Specific-Heat-Example-Problem.htm

opps yes your formula is correct!

To find the specific heat (c) of water, we can rearrange the formula and solve for c.

Using the equation c = q / (m * ΔT):

c = q / (m * ΔT)
c = 14,749 J / (75.0 g * (67.0°C - 20.0°C))

First, we need to calculate the change in temperature (ΔT):

ΔT = final temperature - initial temperature
ΔT = 67.0°C - 20.0°C
ΔT = 47.0°C

Now, we can substitute the values into the equation:

c = 14,749 J / (75.0 g * 47.0°C)

Let's calculate:

c = 14,749 J / (3,525 g°C)

Dividing:

c ≈ 4.18 J / g°C

Therefore, the specific heat (c) of water is approximately 4.18 J/g°C.