-9x+10y=-9
write the equation in slope-intercept form, what are the slope and y-intercept.
I have tried to figure this out but cannot come up with correct answer please help
I got that but what I don't understand is the possible answers are
y=9/10x+9/10;slope;9/10;y-intercept;9/10
y=9/10x-9/10;slope;9/10;y-intercept;9/10
y=-9/10x+9/10;slope;9/10;y-intercept;9/10
y=9/10x-9/10;slope;9/10;y-intercept;-9/10
10 y = 9 x - 9
y = .9 x - .9
m = .9
b = -.9
To write the equation -9x + 10y = -9 in slope-intercept form, we need to isolate the y variable on one side of the equation.
Start by moving the -9x term to the right side of the equation by adding +9x to both sides:
10y = 9x - 9
Next, divide both sides of the equation by 10 to get y alone:
y = (9/10)x - 9/10
Now, the equation is in slope-intercept form, y = mx + b, where m is the slope and b is the y-intercept.
So, the slope of this equation is 9/10, and the y-intercept is -9/10.
To write the equation in slope-intercept form (y = mx + b), where m is the slope and b is the y-intercept, we need to isolate y on one side of the equation.
Given the equation -9x + 10y = -9, let's start by isolating the term with y on one side.
-9x + 10y = -9
First, subtract -9x from both sides of the equation:
10y = 9x - 9
Next, divide both sides of the equation by 10:
y = (9/10)x - 9/10
Now the equation is in slope-intercept form, y = mx + b, where m = 9/10 is the slope, and b = -9/10 is the y-intercept.
Therefore, the equation in slope-intercept form is y = (9/10)x - 9/10, and the slope is 9/10 while the y-intercept is -9/10.