# algebra

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Calvin invested \$7500 for one year, part 12% annual interest and the rest at 10% annual interest. His total interest for the year was \$890. How much money did he invest at 12%? Show work.

• algebra -

\$X @ 12%.
\$(7500-X) @ 10%

I = 0.12X + 0.1(7500-X) = \$890.
0.12x + 750 - 0.1x = 890.
02x = 890 - 750 = 140
X = \$7,000 @ 12%.

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