In the triangle ABC, the measure of angle A=(5x+3)degrees, the measure of angle B=(8x-2)degrees, and the measure of angle C=(5x-1) degrees. Find the measure of each angle.
since A+B+C=180
(5x+3)+(8x-2)+(5x-1) = 180
18x = 180
x = 10
A,B,C are 53,78,49
To find the measure of each angle in the triangle ABC, we can use the fact that the sum of all angles in a triangle is always 180 degrees.
In this case, the sum of angle A, angle B, and angle C should be equal to 180 degrees.
Therefore, we can write the equation:
(5x + 3) + (8x - 2) + (5x - 1) = 180
Combining like terms:
18x + 0 = 180
Simplifying:
18x = 180
To solve for x, we divide both sides of the equation by 18:
x = 180 / 18
x = 10
Now that we have found the value of x, we can substitute it back into the given expressions to find the measure of each angle:
Angle A = (5x + 3) = (5 * 10 + 3) = 53 degrees
Angle B = (8x - 2) = (8 * 10 - 2) = 78 degrees
Angle C = (5x - 1) = (5 * 10 - 1) = 49 degrees
Therefore, the measure of angle A is 53 degrees, the measure of angle B is 78 degrees, and the measure of angle C is 49 degrees.