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A police car is traveling at a velocity of 15.0 m/s due north, when a car zooms by at a constant velocity of 45.0 m/s due north. After a reaction time 0.700 s the policeman begins to pursue the speeder with an acceleration of 3.00 m/s^2. Including the reaction time, how long does it take for the police car to catch up with the speeder?

  • physics -

    HOW TO:
    formula: ΔX=Vi(t)+ 1/2(a)(t^2)
    what we know:
    Vi= 45.0 m/s
    t= .700 s
    a= 3.00 m/s^2

    ΔX= 32.235 m

  • physics -

    it's supposed to be time, not distance as answer

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