1. Which exponent makes the statement true? 1/5^9 = 5^?
a. 9
b. -9
c. 1/9
d. - 1/9
2. y^5 x y^14 =
a. 2y^19
b. y^60
c. y^19
d. 2y^60
3. w^12/w^18 =
a. w^30
b. w^-30
c. w^6
d. w^-6
5. 5^5/5^2 =
a. 5^1
b. 5^2
c. 5^3
d. 5^4
Please help me this is all like greek too me. My teacher taught me how and i still don't get it.
nca students: I know this is right. sure there are other crazy answers out there but these answers are recent and correct
b
c
d
a
a
most likely someone on this page has written that already but this something you can trust
Number 4 and 5 is not a
Jazzzmin is correct
Sure! I'll be happy to help you understand how to solve these problems.
1. To find the missing exponent that makes the equation true, you need to know the rule for dividing with exponents. When you divide two terms with the same base, you subtract their exponents. So, in this case, you have 1/5^9 = 5^?. Since 1 is the same as 5^0, we can rewrite the equation as 5^0 / 5^9 = 5^?. By applying the division rule, we subtract the exponents: 5^(0-9) = 5^?. Simplifying further, we get 5^(-9) = 5^?. Therefore, the correct answer is (b) -9.
2. In this problem, you need to apply the rule of combining exponents when multiplying. When you multiply two terms with the same base, you add their exponents. So, we have y^5 multiplied by y^14. Applying the rule, we add the exponents: y^(5+14) = y^(19). Therefore, the answer is (c) y^19.
3. For this problem, you'll use the rule of subtracting exponents when dividing. You have w^12 divided by w^18. According to the rule, you subtract the exponents: w^(12-18) = w^(-6). Therefore, the answer is (d) w^(-6).
4. In this problem, you need to apply the rule for dividing exponents again. You have 5^5 divided by 5^2. Using the division rule, we subtract the exponents: 5^(5-2) = 5^3. Therefore, the correct answer is (c) 5^3.
I hope this helps you understand how to solve these exponent problems! Let me know if you have any further questions.
B
C
D
C