physics
posted by martha .
Landing with a speed of 87.7 m/s, and traveling due south, a jet comes to rest in 939 m. Assuming the jet slows with constant acceleration, find the magnitude and direction of its acceleration.
Magnitude of acceleration

a=(v²vₒ²)/2s=(vₒ²)/2s=
=  87.7²/2•939=  4.1 m/s².
v is directed to the south,
a is directed to the north.
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