# college alg

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find the equation of a line that is perpendicular to line y=1/6x+6 and contains point (-7,0)

y=?

please show work so i can see how its done

• college alg -

slope of y = (1/6)x + 6 is 1/6
so slope of perpendicular is -6

equation is y = -6x + b
but (-7,0) lies on it
0 = -6(-7) + b
b = -42

y = -6x - 42

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