Jake puts pennies into a jar each morning and lets his brother take haft of the pennies out each morning. Jake put 10 pennies into the empty jar on Monday morning. On Tuesday he put in 15 pennies. One Wednesday he put in 12 pennies. How many pennies are in the jar on Thursday morning before Jake puts his pennies in?
a) 37 pennies
b) 18 pennies
c) 11 pennies
d) 19 pennies
Monday morning: Jake put 10 pennies - his brother took haft - 5
Tuesday Morning: he puts 15 pennies - his brother took haft - 7.5 (that's haft of 15, you divide by 2)
Wednesday Morning: he put in 12 pennies - his brother took haft - 6
I need help!!!! Please help me
I don't get this question.
Monday Jake put in 10 pennies and his brother took out 5, leaving 5 pennies.
Tuesday, Jake put in in 15 pennies, so the jar now has 20 pennies. The brother takes out 10, leaving 10.
Wednesday, he put in 12, now totalling 22; his brother took out half -- leaving 11 pennies.
ohh
thank you soo much
You're very welcome.
To solve this question, let's keep track of the number of pennies in the jar after each morning.
On Monday morning, Jake puts 10 pennies into the empty jar. So, there are 10 pennies in the jar.
On Tuesday morning, Jake puts in 15 pennies. Since his brother takes half of the pennies out each morning, we need to subtract half of 15. Half of 15 is 7.5, as you correctly calculated. So, after Tuesday morning, there are 10 - 7.5 = 2.5 pennies in the jar.
On Wednesday morning, Jake puts in 12 pennies. Again, we need to subtract half of 12. Half of 12 is 6. So, after Wednesday morning, there are 2.5 - 6 = -3.5 pennies in the jar.
Since we can't have negative pennies, let's assume the jar has 0 pennies on Wednesday morning.
Now, let's analyze what happens on Thursday morning. We know that Jake puts his pennies in, but we don't know the exact number. However, we do know that the jar had 0 pennies on Wednesday, so Jake puts in at least 0 pennies on Thursday.
Therefore, the correct answer is either a) 37 pennies or b) 18 pennies.