I know how to do these equations but can't figure these out
(x+3)/5=(x-2)/4
2x squared + 14x =0
To solve the equations you mentioned, let's take them one by one:
1. (x+3)/5 = (x-2)/4:
To begin, you can cross-multiply to get rid of the fractions. Multiply both sides of the equation by 5 and 4 to eliminate the denominators:
4(x+3) = 5(x-2)
Now, distribute the numbers to simplify the equation:
4x + 12 = 5x - 10
Next, isolate the x terms on one side of the equation by subtracting 4x from both sides:
12 = x - 10
Add 10 to both sides to isolate the x term:
22 = x
So, the solution to the equation is x = 22.
2. 2x^2 + 14x = 0:
In this equation, you can factor out the common factor of 2x:
2x(x + 7) = 0
To have a product equal to zero, at least one of the factors on the left side must be zero. This means that either 2x = 0 or x + 7 = 0:
1. 2x = 0
By dividing both sides of the equation by 2, you get x = 0 as a solution.
2. x + 7 = 0
To solve for x, subtract 7 from both sides of the equation:
x = -7
So, the solutions to the equation are x = 0 and x = -7.