calculus

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I need help with the following problem: From a point 50 meters from the bottom of a radio tower along level ground, the angle of elevation to the top of the tower is 67 degrees. What is the height of the tower?

  • calculus -

    think back, back, back to your days in trig.

    If the tower has height h,

    tan 67 = h/50
    h = 117.8 m

  • calculus -

    to solve this problem we need trigonometry therefore takes the radiant
    67°*3,14/180=1,17 rad.= a
    point P=50m
    height tower H=?
    L=hypotenuse of the right triangle LPH
    P=Lcos(a)=> (i)L=p/cos(a)
    (ii)H=Lsen(a)
    (i)+(ii)H=[p/cs(a)]*sn(a)
    tan(a)=sn(a)/cs(a)===>H=p*tan(a)=118m

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