physics
posted by Anonymous .
a steel beam is 12.0 m long when installed at 23 degrees celsius.Find the change in the beam's length if the temperature changes from 32.0 degrees celcius to 55 degrees celcius?

Cooling from 23ºC to 32ºC
ΔL1= α•L•ΔT1 =12•12•10^3•[23(32)]=
=12•12•10^3•55= 7.92•10^3 m
Heating from 23ºC to +55ºC
ΔL2= α•L•ΔT2 =12•12•10^3•[5523]=
=12•12•10^3•32= 4.61•10^3 m
Chamge in the beam’s length is
ΔL=ΔL1+ ΔL2=7.92•10^3+ 4.61•10^3=
=1.253•10^2 m.
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