Physics(Please check)

posted by .

An experiment was done where a tiny steel ball was measured with a micrometer. I know I already posted a question about this before and was given a respond but after trying to fix my answers I am still lost. If someone could please review my results and tell me where I went wrong. Thank you very much.

1) For the D(mm) my results were: Trial 1= 15.90, tr 2= 16.01, tr 3 = 16.0, tr 4 = 16.0 and trial 5 = 15.9 , average=15.9

2) For V=1/2(pi)D^3: trial 1= 2019 , tr 2 = 2061, tr 3 = 2058, tr 4 = 2058, trial 5 = 2019, average 2043. I just plugged in each D value into the equation.

3) |dvi|= |Vi - V(the mean of volume)|: Trial 1 = 24 , tr 2= 18, tr 3 = 15, tr 4 =15, trial 5 = 24, average= 19.2
For this I took the average volume and subtracted it from each volume for each trial.

4) m(g) : Trial 1 = 16.1 , tr 2 = 15.8, tr 3 = 16.0 , tr 4 = 15.6, trial 5 = 15.9, average= 15.9. For this I had to weigh the ball using a scale.

5) Density (g/mm^3) : Trial 1= 8.0, trial 2 = 7.7, tr 3 = 7.8 , tr 4 = 7.6 , trial 5 = 7.9, average = 7.8
For this I divided each mass by volume of every trial.

6) This is where I am confused. |dpi|= |density1 - the mean of density|. For this I took the average density which was 7.8 and subtracted it from each density for the 5 trials.
Trial 1 = 0.1, trial 2 = 0.2, tr 3 = 0.1, tr 4 = 0.1, trial 5 = 0.1, average= 0.12

7) Now it says to compare the measured mean of density (D with the line above) with accepted Density for Fe(7.8 X 10^3 kg/m^3) and calculate the percent error.

I converted 0.12 g/mm^3 into kg/mm^3 and then subtracted that from 7.8X10^3 and then divided by 7.8 X 10^3 and my error was extremely high.

Is my data just incorrect or did I do the calculations wrong?

  • Physics(Please check) -

    Please diregard. I found my mistake.

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

  1. Computer Questions

    I posted some computer questions and my answers on Saturday. They should be on somewhere between pages 2 through 10. would you please check my answers for me?
  2. PHYSICS

    Could u help with physics hw! i keep trying but i keep getting the wrong answer?
  3. physics

    a crane drops a .3 kg steel ball onto a steel plate. the ball's speeds just before impact and after are 4.5 m/s and 4.2 m/s respectively. If the ball is in contact with the plate for .03 s, what is the magnitude of the average force …
  4. physics

    A 8.5 kg steel ball, travelling left to right at 12 m/s, undergoes an elastic collision with a 5 kg steel ball at rest. To the nearest Joule, what is the Total Kinetic Energy of the two balls after collision?
  5. Physics(Please help, thank you)

    I had to do an experiment where a tiny steel ball was measured using a micrometer. There was then a series of calculations that needed to be completed and then a percent error had to be calculated. I think that my data may be incorrect …
  6. Physics(Please help, thanks)

    An experiment was done where a tiny steel ball was measured with a micrometer. I know I already posted a question about this before and was given a respond but after trying to fix my answers I am still lost. If someone could please …
  7. chemistry

    Hi, I was hoping someone could double check a chemistry answer for me. I am trying to calculate the Ksp of Ag2CrO4. This question is based on a experiment to determine ksp experimentally. In the experiment the Ksp of silver chromate …
  8. physics

    a crane drops a 1.0 kg steel ball onto a steel plate. the ball's speed just before impact is 2.0 m/s. if the average impact force is 300 N, and the ball is in contact with the plate for 0.01 seconds, what is the bounce back speed right …
  9. TO MS SUE

    Please check my answers to my question, I posted this question before but no one answered or helped me. All I need is for someone to check my answers :)
  10. Physics

    In an inelastic collision, a steel ball of mass 200 g was hit hard into a large ball of dough of mass 700 g. The velocity of the steel ball was 25m/s. After the collision, the steel ball was stuck in the dough, and this combined system …

More Similar Questions