algebra

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Briana's second test score was 8 points higher than her first score. Her third score was 88. She had a B average (between 80 and 89 inclusive) for three tests. What can you conclude about her first test score?

  • algebra -

    i set the equation end give you the solutions but you try to get there

    x=first test, y=second test z= three test

    i)second test score was 8 points higher than her first score => y=x+8
    ii)Her third score was 88=> z=88
    iii)B average (between 80=> B=(x+y+z)/3<80
    iiii)B average...and 89 inclusive)=> B=(x+y+z)/3>89

    advice: replace i and ii in disequations iii and iiii

    solution x>72 x<85,50

  • algebra -

    sorry.....errata corrige:
    iii)B average (between 80=> B=(x+y+z)/3>80
    iiii)B average...and 89 inclusive)=> B=(x+y+z)/3<89

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