chemistry

posted by .

A flask containing 5.00ml of 3M hcl solution required 14.45 of 1.00M naoh for titration. How many moles of hcl are present in the solution? The density of 3M hcl is 1.05g/ml.

My calculation

0.005L x 3M = 0.015 moles
0.01445 x 1m = 0.01445 moles

Who helps me to solve it

  • chemistry -

    See your post above.

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

  1. chemistry

    A flask containing 5.00mL of 3 M HCl solution requires 14.45mL of 1.00 M NaOH for titration. How many moles of HCl are present in the solution?
  2. chemistry

    A flask containing 5.00mL of 3 M HCl solution requires 14.45mL of 1.00 M NaOH for titration. How many moles of HCl are present in the solution?
  3. CHEMISTRY TITRATION Q

    The titration of 25.00mL of Ba(OH)2 solution with an aqueous solution of 0.500 M HCl reaches an end point when 30.20 mL of the HCl solution is added. Determine the concentration of M of the Ba(OH)2 solution. Soo 25.00mL=0.025L 30.20mL= …
  4. chemistry

    In a titration experiment, 22.00mL of a NaOH solution are required to neutralize 24.02 mL of a 0.1094 M HCL solution. what is the molarity of H+ in the HCL solution?
  5. Chemistry - titration lab

    Hello. For my chemistry of solutions class, we had a titration lab where we titrated NaOH into an HCl + H2O mix. This was a preparatory titration for the next one consisting of the hydrolysis of ethyl acetate into acetic acid with …
  6. chemistry

    A flask containing 5ml of 3M hcl solution required 14.45ml of 1M NAOH for titration. How many moles of hcl are present in the solution. The density of 3M hcl is 1.05g/ml My calculation 0.005 x 3 = 0.015m 0.01445 x 1 = 0.01445m Who …
  7. chemistry

    titration question: How many moles of HCl must have been present in the 25mL of HCl solution in the 2 trials?
  8. Chemistry - Solubility

    INFORMATION: [HCl] = 0.1388 M We placed 0.5 g Ca(OH)2 in 100 mL of the following solutions: Flask A: Distilled Water (7.4 mL of HCl needed to titrate) Flask B: 0.05 M NaOH (7.5 mL of HCl needed to titrate) Flask C: 0.025 M NaOH (10.8 …
  9. Chemistry - Solubility

    INFORMATION: [HCl] = 0.1388 M We placed 0.5 g Ca(OH)2 in 100 mL of the following solutions: A 25 ml aliquot was used Flask A: Distilled Water (7.4 mL of HCl needed to titrate) Flask B: 0.05 M NaOH (7.5 mL of HCl needed to titrate) …
  10. chemistry

    A student prepares a solution of hydrochloric acid that is approximately 0.1 M and wanted to determine its precise concentration. A 25.00 mL portion of the HCl solution is transferred to a flask, and after a few drops of indicator …

More Similar Questions