Calculate the heat outflow when 2 kg of dry saturated steam at 8.0 bar is converted into ice at -lO0C.
Dry saturated steam sounds like an oxymoron to me.
How did you get on with this? Is there a formula?
Thanks
To calculate the heat outflow, we need to determine the heat transferred during two processes:
1. Cooling the steam from 8.0 bar to 100 degrees Celsius.
2. Freezing the water at 100 degrees Celsius into ice at -10 degrees Celsius.
To find the heat transferred during each process, we can use the specific heat capacity and latent heat of vaporization.
Step 1: Cooling the steam to 100 degrees Celsius
1. Determine the initial temperature of the steam. Since it is saturated steam, it is at its boiling point of 100 degrees Celsius.
2. Use the specific heat capacity of water (4.186 J/g°C) to calculate the heat transferred during this process.
Heat1 = mass of steam * specific heat capacity * temperature change
Step 2: Freezing the water at 100 degrees Celsius into ice at -10 degrees Celsius
1. Determine the mass of water that needs to be frozen. Since we have 2 kg of steam, all of it will be converted into water at 100 degrees Celsius.
2. Calculate the heat transferred by using the latent heat of vaporization of water (2260 J/g) and the mass of water.
Heat2 = mass of water * latent heat of vaporization
Finally, the total heat outflow is the sum of the heat transferred in the two steps:
Total heat outflow = Heat1 + Heat2
Using the specific values for the specific heat capacity and latent heat of vaporization, you can substitute the values and calculate the heat outflow.