Not only need answer but need to know how you teach a 5th grader how to solve this problem.
You can only use the digits 0-9. I need an odd number that is a multiple of five with no repeated digits. Half the digits are odd and the other half is even. The largest digit in the number is in the tens place (but it is not the largest digit). The digit in the hundreds place is half the digit in the tens place. The sum of the digits is greater than 20.
The number is odd, and divisible by 5 - so the final digit must be 5.
The largest digit is in the tens place, but isn't the largest digit, and no digits are repeated - so it must be 6, 7 or 8. The digit in the hundreds place is half the digit in the tens place, so the digit in the tens place must be even - so it must be 6 or 8, and the digit in the hundreds place must correspondingly be 3 or 4.
The number must have an even number of digits because there are the same number of odd digits as even ones. Suppose it's got exactly four digits. Call it ABCD. We know that D=5, so it's ABC5. Since the total of the digits is greater than 20, we're probably looking for large digits - so let's assume that the digit in the tens place is 8, and therefore that the digit in the hundreds place is 4. That would make our number A485. A must now be odd, but it can't be 9 (because that would make it the largest digit), so it must be 1, 3 or 7. That would make the answer 1485, 3485 or 7485. But only the third of these totals to more than 20, so the answer must be 7485.
It's just as well that you can only use the digits 0-9 to solve this problem, since there aren't any others :)
20.007 in expanded form
To solve this problem for a 5th grader, we can break it down into smaller steps:
Step 1: Determine the range of numbers we can use.
Since we can only use the digits 0-9, we need to find a combination of these digits that meets all the given conditions.
Step 2: Find the odd multiples of five.
Start by listing down all the odd multiples of five, beginning with 5: 5, 15, 25, 35, 45, 55, and so on.
Step 3: Eliminate numbers with repeated digits.
Go through the list of odd multiples of five and eliminate any numbers with repeated digits. For example, 55 has repeated digits, so we should remove it from our list.
Step 4: Prime the list with numbers that have the largest digit in the tens place.
From the remaining list, identify numbers that have the largest digit in the tens place. For example, 35 has the largest digit (3) in the tens place.
Step 5: Identify numbers where the digit in the hundreds place is half the digit in the tens place.
Look for numbers where the digit in the hundreds place is half the digit in the tens place. In our case, the digit in the hundreds place should be 1. So, we can eliminate any numbers that don't meet this condition.
Step 6: Check the digits for even and odd distribution.
Check the remaining numbers to ensure that half of the digits are odd and the other half is even. For example, in the number 35, 3 is odd while 5 is odd as well. If the digit distribution is not even, remove that number from the list.
Step 7: Check the sum of the digits.
Finally, calculate the sum of the digits for each remaining number and remove any numbers where the sum is less than or equal to 20.
Step 8: Choose the final answer.
If you have more than one number left after following the steps above, select the largest number as your final answer based on the condition that the largest digit is in the tens place (but not the largest overall digit). Otherwise, if there is only one number left, it is your final answer.
Using this step-by-step approach, you should be able to find the odd multiple of five that meets all the given conditions.