A solution was prepared by dissolving 8.0g of solid ammonium sulfate (MW= 132.14, specific volume= 0.565ml/g) in 35ml (i.e 35g) of water.
What is the final volume of the solution?
0.565 mL/g x 8.0g = ? mL.
35 mL + ?ml = ? mL total volume.
Check my thinking.
To find the final volume of the solution, we need to consider the volume of the solid ammonium sulfate and the volume of the water.
1. Calculate the volume of solid ammonium sulfate:
Volume of solid ammonium sulfate = mass of solid / specific volume
Volume of solid ammonium sulfate = 8.0 g / 0.565 ml/g = 14.16 ml
2. Calculate the total volume of the solution:
Total volume = volume of solid ammonium sulfate + volume of water
Total volume = 14.16 ml + 35 ml = 49.16 ml
Therefore, the final volume of the solution is 49.16 ml.
To find the final volume of the solution, we need to consider the volume of the solid ammonium sulfate and the volume of water.
The volume of the solid ammonium sulfate can be calculated using its specific volume, which is given as 0.565 ml/g. We are given that 8.0 g of solid ammonium sulfate was dissolved. Therefore, the volume of the solid ammonium sulfate is:
Volume of solid ammonium sulfate = Mass / Specific volume
= 8.0 g / 0.565 ml/g
= 14.16 ml
Next, we need to consider the volume of water, which is given as 35 ml.
To find the final volume of the solution, we add the volume of the solid ammonium sulfate to the volume of water:
Final volume of the solution = Volume of solid ammonium sulfate + Volume of water
= 14.16 ml + 35 ml
= 49.16 ml
Therefore, the final volume of the solution is 49.16 ml.