A model helicopter of mass 5kg rises vertically from rest to a height of 60m with a constant acceleration in 10 seconds. Calculate the total thrust with which the helicopter rises.
h=at^2/2
a=2h/t^2
F= ma
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What is the answer to this question
To calculate the total thrust with which the helicopter rises, we can use the equations of motion.
Step 1: Find the acceleration (a) of the helicopter.
Given that the helicopter rises vertically with a constant acceleration in 10 seconds, we can use the equation:
s = ut + (0.5)at^2
where s is the displacement (60m in this case since the helicopter reaches a height of 60m), u is the initial velocity (0 m/s since the helicopter starts from rest), t is the time (10s in this case), and a is the acceleration (which we want to find).
Plugging in the values, we have:
60 = 0(10) + (0.5)a(10)^2
Simplifying the equation, we get:
60 = 0 + 50a
Dividing both sides by 50, we get:
a = 60/50 = 1.2 m/s^2
So, the acceleration of the helicopter is 1.2 m/s^2.
Step 2: Calculate the total thrust.
The total thrust (T) acting on the helicopter is equal to the mass (m) of the helicopter multiplied by its acceleration (a). In this case, the mass of the helicopter is given as 5 kg, and the acceleration is 1.2 m/s^2, which we found in step 1.
T = m * a
T = 5 kg * 1.2 m/s^2
T = 6 N
Therefore, the total thrust with which the helicopter rises is 6 Newtons.