calculus
posted by student .
The point P(4, −2)lies on the curve y = 2/(3 − x).
(a) If Q is the point(x, 2/(3 − x)),use your calculator to find the slope mPQ of the secant line PQ (correct to six decimal places) for the following values of x.
1) 3.9 mPQ=
2) 3.99 mPQ=
3)3.999 mPQ=
4) 4.1 mPQ=
5) 4.01 mPQ=
im so confused! i just started this and my teacher really didn't explain it. can someone please break this down for me?

I will do one of them, you do the others
3) x = 3.999
then y = 2/(33.999) = 2.00200200200...
then slope = (2.002002002  (2))/(3.9994)
= 2.0020020.. 
thank you for answering me. im just trying to figure this out. i understand how the part y= 2/(33.999) = 2.002002002
just your second line im trying to figure out. i can do the others once i just understand the steps. my teacher didn't go over this unfortunately. 
nevermind i understand i took another look at it and its clear. thank you so much for getting back to me!!

we now had two points
the original (4,2) and
the new (3.999, 2.002002002)
(notice that these two points are practically on top of each other)
how do you find the slope between 2 point ?
if we had 2 points ( a,b) and (c,d) wouldn't it
be (db)/(ca) or
you might have been taught
(y2  y1)/(x2  x1)
that's all I did.