algebra college
posted by ash .
find the remaining zeros of f.
degree 4 zeros i, 18+i
enter the remaining zeros of f
please help me out!

complex roots always come in conjugate pairs,
so the roots are ±i and 18+i and 18i
so you would have
(x+i)(xi)(x+ 18i)(x+18+i)=0
(x^2 + 1)(x^2 + 18x + xi + 18x + 324 + 18i  xi  18i  i^2) = 0
(x^2 + 1)(x^2 + 36x +324 + 1) = 0
(x^2 + 1)(x^2 + 36x + 325) = 0
expand again, and simplify