Math
posted by KC .
An isosceles triangle has its vertex at the origin and the ends of its base on the parabola y=9x^2. Express the area of the triangle as a function of the length of its base. Assume its base lies above the xaxis.

a = 1/2 bh
Assuming the base of the triangle is parallel to the xaxis, then
a = 1/2 b (9  b/2)^2
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