posted by KC .
An isosceles triangle has its vertex at the origin and the ends of its base on the parabola y=9-x^2. Express the area of the triangle as a function of the length of its base. Assume its base lies above the x-axis.
a = 1/2 bh
Assuming the base of the triangle is parallel to the x-axis, then
a = 1/2 b (9 - b/2)^2