posted by Don .
I need help with the following question: While fishing on a lake, you see a fish below water at a 25 degree angle with the surface, producing air bubbles on the surface of the water 20 feet ahead. How far away is the fish from the boat?
Assuming we are not taking Snell's Law into account, the distance d is given by
sec 25° = x/20
x = 22.07 ft