On your wedding day your lover gives you a gold ring of mass 3.68 g. 54 years later its mass is 3.28 g. On the average how many atoms were abrated from the ring during each second of your marriage? The atomic mass of gold is 197 u.

Please refer to my previous answer to the same question.

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To calculate the average number of atoms abraded from the gold ring during each second of your marriage, we need to use a few steps:

Step 1: Calculate the change in mass of the ring.
Change in mass = Initial mass - Final mass
Change in mass = 3.68 g - 3.28 g
Change in mass = 0.4 g

Step 2: Convert the change in mass to kilograms.
Change in mass (in kg) = 0.4 g / 1000
Change in mass (in kg) = 0.0004 kg

Step 3: Determine the number of moles of gold lost from the ring.
Number of moles = Change in mass / Atomic mass of gold
Number of moles = 0.0004 kg / 197 g/mol
Number of moles = 2.03 x 10^-6 mol

Step 4: Convert the number of moles to the number of atoms.
Number of atoms = Number of moles x Avogadro's constant
Number of atoms = 2.03 x 10^-6 mol x 6.022 x 10^23 atoms/mol
Number of atoms = 1.22 x 10^18 atoms

Step 5: Calculate the average number of atoms abraded from the ring per second.
Average number of atoms abraded per second = Number of atoms / Number of seconds
(Note: 54 years has to be converted to seconds)
Number of seconds = 54 years x 365.25 days/year x 24 hours/day x 60 minutes/hour x 60 seconds/minute
Number of seconds = 1.71 x 10^9 seconds

Average number of atoms abraded per second = 1.22 x 10^18 atoms / 1.71 x 10^9 seconds
Average number of atoms abraded per second ≈ 7.13 x 10^8 atoms

Therefore, on average, around 7.13 x 10^8 atoms were abraded from the gold ring during each second of your marriage.