posted by Daisy .
A man jogs at a speed of 1.7 m/s. His dog
waits 2.5 s and then takes oﬀ running at a
speed of 4.1 m/s to catch the man.
How far will they have each traveled when
the dog catches up with the man?
help me set up the equations please!
s= v1• (t+2.5) = v2•t
= 2.5•1.7/(4.1-1.7)=1.77 s.
s =v2•t=4.1•1.77=7.26 m